How to drop a Spaceforcibly using the Java API.
Article ID: KB0092969
Updated On:
| Products | Versions |
|---|---|
| TIBCO ActiveSpaces | - |
| Not Applicable | - |
Description
Description:
An ActiveSpaces Space cannot be dropped if any member has already connected. To forcibly drop a Space, make all joined members leave the space iterativley.
Resolution
As there is no instance command or API to do this, use the following workarounds:
A). Using a Command:
1). List all joined members for a space with the command 'show space <space_name>' .
2). Execute the 'leave space' command on each member with command 'execute on member <member_name> leave space <space_name>' .
B). Using the API:
1). Iterate all members of a space.
2). To invoke the Admin command, 'execute on member <member_name> leave space <space_name>' .
Here is a snippet of the code (Java):
================================
try
{
// Introduce the com.tibco.as.admin.Admin
Admin admin = Admin.create();
String space_name = "";
if (space != null && listener != null) space.stopListener(listener);
if (space != null) {
space_name = space.getName();
if (metaspace != null) {
// Iterator all of members of a space
Collection<Member> m = space.getMembers();
Iterator it = m.iterator();
while(it.hasNext()){
Member _m = (Member)it.next();
try {
// execute the 'leave space' command on each member
admin.execute(metaspace, "execute on member '"+ _m.getName() +"' leave space '"+space_name+"'");
} catch (AdminException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
space.closeAll();
}
}
if (metaspace != null) {
// drop the space
metaspace.dropSpace(space_name);
metaspace.closeAll();
}
}
catch (ASException ex)
{
ex.printStackTrace();
}
=================================
Issue/Introduction
How to drop a Spaceforcibly using the Java API.
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